How do I graph a function? 
06.04.2015, 14:10  ms.srki  Auf diesen Beitrag antworten »  
How do I graph a function? Point A=a , point B=x , straight line AB=? 

06.04.2015, 14:30  Hippocampus  Auf diesen Beitrag antworten »  
Do you have any idea? You should draw or at least imagine a sketch. 

07.04.2015, 12:49  ms.srki  Auf diesen Beitrag antworten »  
Removed full quote. Steffen solution, in my opinion current graph is as follows to look at the graph of a level different from the above ? notation :  constants or variables are on the x  coordinate  constants or variables are on the y  coordinate 

08.04.2015, 13:23  ms.srki  Auf diesen Beitrag antworten »  
The graph function from the xcoordinates of the plane (Cartesian coordinate system) , and remain on the xcoordinate, goes to the ycoordinate . coordinates of the points straight line view photo [attach]37674[/attach] the lines of x and a parallel to the ycoordinates line of y parallel to the xcoordinate formed at the intersection of real points A and B points A and B are combined and gets straight line AB is given by Repeat for , view photo formed at the intersection of real points C and D points C and D are combined and received straight line CD [attach]37675[/attach] connect the dots AC (BD) straight lines AB and CD ABDC points form the surface of Draw a graph of the function at the current proceedings for 

08.04.2015, 15:03  Steffen Bühler  Auf diesen Beitrag antworten »  
So, for y=xa, you got the four points A(2;42), B(4;42), C(2;3.52), and D(3.5;3.52). Now, its ax instead of xa. Here, for instance, A becomes (2;24). See? Now calculate the three other points and draw. Next comes ax which means A becomes (2;2) and so on. Regards Steffen 

08.04.2015, 16:24  ms.srki  Auf diesen Beitrag antworten »  
Removed full quote. Steffen You understand the process, we need to draw a graph for each , as a whole 

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08.04.2015, 16:48  Steffen Bühler  Auf diesen Beitrag antworten »  
So you want to assign a 2D shape to every x value? This would result in a 3D diagram, I guess. For each x, you get a respective polygon in the yz plane. You could then render this set of polygons. Is this what you want? 

08.04.2015, 18:27  ms.srki  Auf diesen Beitrag antworten »  
Removed full quote. Steffen will receive the 2D surface for each x , will not be obtained a 3D diagram , I want you able to give the graph of the conditions that have given . 

08.04.2015, 21:22  Steffen Bühler  Auf diesen Beitrag antworten »  
I must confess I didn't understand your last post. 

09.04.2015, 11:07  ms.srki  Auf diesen Beitrag antworten »  
Removed full quote. Steffen I've said it looks like this graph, the red surface [attach]37678[/attach] graph, the red surface [attach]37679[/attach] graph, the red surface [attach]37680[/attach] graph, the red surface [attach]37681[/attach] graph, the red surface [attach]37682[/attach] which are geometric objects obtained for valuesx and y , shape ( )? , you have a graph 

09.04.2015, 11:49  Steffen Bühler  Auf diesen Beitrag antworten »  
Do you need a mathematical formula for, e.g. this red surface? [attach]37678[/attach] This is the set of all pairs (x;y) where y>2x: Did I now get it right? PS: if you answer me, don't quote me, just answer. I'll remove your full quotes for the sake of clarity. 

09.04.2015, 14:44  ms.srki  Auf diesen Beitrag antworten »  
what did you draw the current graph , y=2x [attach]37678[/attach] I am drawn by the rules , graph is not as in classical mathematics, obtained points in the plane , for me it gets straight lines in the plane I hope you realize what it is 

09.04.2015, 15:01  Steffen Bühler  Auf diesen Beitrag antworten »  
The graph of the function y=2x is only to show that the inequality y>2x perhaps is what you need in this case. As you said, this is not a function (there's more than one y value for one x value), but can be written as a set: { (x,y)  y>2x } which is exactly the red surface in your drawing. So, if your question is how to express the graph mathematically, this is the answer. Otherwise, please tell us your question, maybe in another thread, and maybe in German. I hope someone else can help you here. Regards Steffen 

10.04.2015, 18:04  ms.srki  Auf diesen Beitrag antworten »  
a) b), the same graph is reversed only to , and relates to a negative value y rectangular isosceles triangle [attach]37696[/attach] regular trapeze [attach]37697[/attach] rectangular trapeze [attach]37698[/attach] pentagon [attach]37699[/attach] more geometric objects that can be obtained ??? 

13.04.2015, 11:38  ms.srki  Auf diesen Beitrag antworten »  
Operations on sets  difference, this operation returns a new geometric objects , hexagon [attach]37712[/attach] heptagon [attach]37713[/attach] trapezoid and triangle together [attach]37714[/attach] that even mathematical topic can be displayed through the graphics functions (part) ? 

13.04.2015, 12:33  Steffen Bühler  Auf diesen Beitrag antworten »  
Like I said, I can't help you. Maybe someone else will answer here, but it's surely better to start a new thread (in German, if possible) and ask a clear question. Up to now, I still don't know what you want to do. Best regards Steffen 

14.04.2015, 18:10  ms.srki  Auf diesen Beitrag antworten »  
The symmetry of geometric object trapez  [attach]37735[/attach] to make it look a graph 

18.04.2015, 18:55  ms.srki  Auf diesen Beitrag antworten »  
[attach]37761[/attach]  [attach]37762[/attach] 

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